
adccommunitymod (AutomationDirect) asked a question.
Created Date: October 21,2012
Created By: jeganjwm
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For a centrifuge operation( 1 mtr Dia) we have purchased PARKER make , 25 KW AC Drive to drive 18 HP ,975 RPM Induction Motor and it should stop after every 120 Secs we programmed accordingly. But drive is not stopping( Deceleration time 45 Secs) (stops but shaft rotating due to High inertia) Trip indication High DC So we planned to connect DBR after calculation we came to know the Inertia is 150 NM-KG2 and Regeneration power is 18KW. In the PARKER drive manual, there is no such high wattage (18 KW) DBR all are below 3 KW .When we try to get out side , DBR dealers tells that we should change the CHOPPER of Drive also to handle that much power dissipation. Please help me any one who faced the same problem or those who knows
Created Date: October 22,2012
Created by: jwbaker3
We design and install special drive and motor packages for test stands. (150 to 1000hp with shaft speeds to 15000 rpm) When we have a high load we need to stop offen we use a regen unit to put the power produced by the motor back on the line. When the drive is slowing the motor and the load is trying to spin the motor faster than the drive, the motor becomes an induction genatator putting power back thru the IGBT's in the drive driving up the D.C. bus voltage in the drive, this power must be reduced by braking reisitors (turned into heat) or regen unit (put back thru a set of IGBT's and returned to the power lines) or if there are more that one drive you can tie the d.c. buses together and load share (one drive in regen mode while the other is motoring so the power is used by another drive on the dc bus, special care with system design must be used to do this) There are stand alone units that will connect to the dc bus on the drive. Most major drive mfj make one, I am sure Parker has one but there are stand alone units like Bonitron that you can match to your drive. With the proper regen unit you can stop the motor quickly and put the power produced by the motor back on your power grid. I have used the Bonitron ( www.bonitron.com ) units before but we normaly use Yaskawa or Unico drive for these projects. Hope this helps.
JW
Created Date: October 25,2012
Created by: jeganjwm
DBR calculation
plse help me
how to calculate DBR for 18 kw regeneration power during stopping of inductin motor with AC drive
Created Date: October 25,2012
Created by: Bob S BN
Not trying to be rude, just trying to get you the help you need in this specific application soon.
I would suggest you talk to the Parker folks about this problem with the Parker drive.
Perhaps they have a user forum similar to this one that Automation Direct hosts for users of their components.
I could be wrong, but I don't think you'll find a lot of Parker drive users with the kind of details you 're looking for on this forum.
Created Date: October 27,2012
Created by: milldrone
For a centrifuge operation( 1 mtr Dia) we have purchased PARKER make , 25 KW AC Drive to drive 18 HP ,975 RPM Induction Motor and it should stop after every 120 Secs we programmed accordingly. But drive is not stopping( Deceleration time 45 Secs ) (stops but shaft rotating due to High inertia) Trip indication High DC
So we planned to connect DBR after calculation we came to know the Inertia is 150 NM-KG2 and Regeneration power is 18KW .
Not sure if it's a language thing or maybe I'm just confused in my old age. Some of your statements seem odd to me.
1. You indicate that it should or needs to stop at 120 seconds, and in the next statement you mention 45 seconds and a fault. Is the decell ramp 120 seconds or 45 seconds?
2. I find it odd that you can get 18 KW of regen from a 18 hp motor last time I looked 1 hp = 746 watts.
Created Date: October 29,2012
Created by: jwbaker3
If you dont want to use a regen unit I agree with Bob you need to contact Parker, normally the max you can use (off the shelf) a dynamic braking resistor is 10% duty cycle. Any thing above that you will need to get Parker to help.
JW
Created Date: November 05,2012
Created by: Tom Jenkins
I 've had some experience with high inertia loads (but not as high as yours!). My SOP:
1) Keep extending accell and decell times until you no longer get high current trips on accell and high DC bus voltage on decell. These trips can occur during normal speed adjustments if you have them set too low, not just at stopping.
2) Unless you need to have a rapid stop for some reason, don't try to do it with dynamic vraking. That's a lot of kinetic enegy and a lot of heat to dissipate. Why do it if you don't need to?
3) At the very end of the stop cycle you can use DC injection braking to bring the load to a full stop - but don't try it too soon or you will get faults.
4) If the process can handle it, you can always just let the load coast to a stop instead of decelerating it.
Created Date: October 21,2012
Created by: jeganjwm
For a centrifuge operation( 1 mtr Dia) we have purchased PARKER make , 25 KW AC Drive to drive 18 HP ,975 RPM Induction Motor and it should stop after every 120 Secs we programmed accordingly. But drive is not stopping( Deceleration time 45 Secs) (stops but shaft rotating due to High inertia) Trip indication High DC
So we planned to connect DBR after calculation we came to know the Inertia is 150 NM-KG2 and Regeneration power is 18KW. In the PARKER drive manual, there is no such high wattage (18 KW) DBR all are below 3 KW .When we try to get out side , DBR dealers tells that we should change the CHOPPER of Drive also to handle that much power dissipation. Please help me any one who faced the same problem or those who knows